嘘 terrorist: 美国一堆 Meckwell lite 也是 1C*-(1any)-P=0-4 X*=5-7 07/04 07:15
→ terrorist: 未必理论上最佳, 但是明明顶级 pair 就还有很多这么用 07/04 07:20
→ terrorist: 如果没有证据, 可以不要这样做全称的论述吗? 07/04 07:21
这是我的疏失, 讲得太言过其实,
假如参考2001至2022年百慕达冠军pair(这些人作为顶级pair的依据)用的精准制
Rodwell-Meckstroth (2003, 2009)
P = 0-4 HCP.
X = 5-7 HCP.
New suit = suit, FG.
Sontag-Weichsel (2001)
整理资料突然发现, 有好多细节
但看起来不同于P=0-4, X=5-7
1C (1X/2X) - natural
P : 0-5 HCP or penalty double
X : 6+ HCP, can be passed
new suit : natural, forcing
new suit : 5+, 9+ HCP, gf
cue-bid : 9+ HCP, looking for 3N, gf
new suit : 5+, 5-8 HCP
1N : balanced, 6-8 HCP
cue-bid : (1444) or (0445) where short in X, 9+ HCP, gf
2N : balanced, two stoppers, 9+ HCP, gf
jump shift : 6-7, 9+ HCP, gf
double jump shift : excellent 6-7, 9+ HCP, gf
1C (2S/3X) - natural
P : 0-6 HCP or penalty double
X : 7+ HCP, can be passed
new suit : natural, forcing
new suit : 5+, 9+ HCP, gf
cue-bid : 9+ HCP, looking for 3N, gf
new suit : 6+, gf
3N : to play, 10-12 HCP
jump shift : excellent 6-7, gf
2N : balanced, two stoppers, 7-8 HCP
1C (1X/X) - specific two-suiter (showing A and B; E and F are the other two)
P : 0-5 HCP
X/XX : penalty oriented (a la unusual vs. unusual)
cheapest cue : 6-9 HCP, length in C and D, promises another bid
expensive cue : 9+ HCP, length in C and D, gf
1N : balanced, 6-8 HCP
1E/1F : 5+, 5-8 HCP
2N : balanced, 9+ HCP, gf
jump shift : 6-7, 9+ HCP, gf
double jump shift : excellent 6-7, 9+ HCP, gf
1C (1X) - exclusion (shortness in suit X)
X : 4 cards in suit X, 9+ HCP
1N : 4-5 cards in suit X, 6-8 HCP
2X : 5+ in suit X, 9+ HCP, forcing
new suit : 5+, 5-8 HCP
P : 0-8 HCP
followup : X : 6-8 HCP (with no suit)
1C (1X) - transfer to suit above suit X (suit Y)
P : 0-5 HCP
X : 6-8 HCP
1Y : 9+ HCP, gf
1N : stopper in Y, 6-8 HCP
new suit : 5+, 5-8 HCP
2N : two stoppers in Y, 9+ HCP, gf
2Y : stiff or void in Y, 4+ in other suits, gf
jump shift : 6-7, 9+ HCP, gf
double jump shift : excellent 6-7, 9+ HCP, gf
1C (CRASH) - X for Color, 1D for Rank, 1H for Shape
X/XX : balanced, 9+ HCP, sets up heat-seeking auction or gf
new suit : 5+, 9+ HCP, gf
P : 0-8 HCP, forcing
Muller-deWijs (2011)
TARZAN strong club
制度卡没写, 但有个名字可能很特别(?
Grue-Moss (2017)
P = 0-7 HCP.
X = FG.
New suit = TRF(使用S/H/D/C的顺序).
以上5个冠军, 有2个冠军用P = 0-4 HCP. X = 5-7 HCP.
所以只有4成, 其实是少数数被我忽略了.
剩下的6成, 2个冠军用法明显不同, TARZAN没资料所以不知道.
多数派则不这么用.
这个pair不知道算不算精准, 因为他们自称打接力....
竞叫把6-8 HCP切割了, 应该算不同对抗.
Tundal-Groetheim (2007)
1C-(1H)-?
P = 6-8 HCP, 4oM. (1H以上都类推, 所以遇到低花插叫可能是44Ms.)
X = 0-5 HCP.
1S = 6-8 HCP, no 4S.
1N = 9+ HCP, w/ H stopper.
2C = 5+D, inv+.
2D = 5+C, FG.
2H = 5+S, inv+.
2S = 9+ HCP, no/poor H stopper.
2N = 5-7 HCP, 5+S + 5+D.
3C = 6+D, ST.
1S至2N插叫同理类推.