A certain cocket(mass:m), which has an initial speed of zero,
is lauched vertically upward from the earth's surface with uniform thrust
of F.
The thrusr is terminated at time t0 following launch.
Afterwards, what is the highest altitude above the earth attained
by the rocket?
Assume that the change in m and the change in g due to height are negligible.
答案是: F(F-mg)t0^2/( 2m^2 g)
请问一下这题要怎么解呢?
我是用V=V0+at
V=(F-mg)t0/m
mgH=1/2 mV^2
然后把V=(F-mg)t0/m代入上式
可是这样算出来是错的
烦请版友指正
感谢