Re: [理工] 微积分

楼主: a016258 (憨)   2015-06-11 14:17:58
: 2 4
: 2).从原点到曲线(x) (y) =1的最短距离?
x^2 + y^2 = 1/(y^4) + y^2
1/(y^4) + (y^2/2) +(y^2/2)
=>
作者: skyghostlove (Chris)   2015-06-17 07:32:00
谢谢

Links booklink

Contact Us: admin [ a t ] ucptt.com