※ 引述《MICKAAELan (米K)》之铭言：
: 想请教大大一题物理，
: 因为看不懂题意，卡关好久，GOOGLE大神也只帮忙找到付费网站的解答@@
: 拜托各位大大了！
: 题目如下：
: A car is 200 m from a stop sign and traveling toward the sign at 40.0 m/s.
: At this time, the driver suddenly realizes that she must stop the car.
: If it takes 0.200 s for the driver to apply the brakes,
: what must be the magnitude of the constant acceleration of the car after
: the brakes are applied so that the car will come to rest at the stop sign?
: 只能选择一个：
: a. 2.08 m/s^2
: b. 4.17 m/s^2
: c. 3.42 m/s^2
: d. 3.89 m/s^2
: e. 2.89 m/s^2
在踩下刹车所花费的0.2秒时间 车子又行进了40*0.2=8(公尺)
又200-8=192(公尺)
因此在离停止标志尚192公尺之后开始进行等加速度运动
由此带入v^2=v0^2+2ax之公式
得到0^2=40^2-2*a*192
求得a=4.17 (近似值)
有错误请各位前辈指教改正