[试题] 102下 庄武谚 代数导论二 期末考

楼主: acliv (acliv)   2014-07-12 12:07:51
课程名称︰代数导论二
课程性质︰数学系大二必修
课程教师︰庄武谚
开课学院:理学院
开课系所︰数学系
考试日期(年月日)︰103/06/16
考试时限(分钟):150
是否需发放奖励金:是
(如未明确表示,则不予发放)
试题 :
(1) (15 points) Please state the first 3 parts (G1-G3) of the Fundamental
Theorem of Galois Theory. (In the rest of the test G1-G5 could all be
assumed.)
(2) (15 points) Prove that Q(√2+√3) = Q(√2, √3). Show that [Q(√2+√3) : Q]
= 4 and find the minimal polynomial of √2 + √3 over Q.
4
(3) (15 points) Determine the splitting field and its degree over Q for x + 2.
(4) (15 points) Let p(x) be an irreducible polynomial over a field F of
positive characteristic. Then there exists an integer k ≧ 0 and an
irreducible separable polynomial p_sep(x) ε F[x] such that
k
p
p(x) = p_sep(x).
(5) (15 points) Consider the polynomial f(x) = x - 4x -1 ε Z[x]. Show that
f(x) is irreducible by reducing the polynomial to F_3[x]. Please compute
the Galois group of f(x) over Q and then determine its solvability by
radicals.
(6) (15 points) Let K be a degree n cyclic field extension over F, which
n
contains n-th roots of unity. Prove that K = F(√a) for some a ε F.
(7) (15 points) Let K/F be a Galois extension and F'/F be any extension. Prove
that KF'/F' is Galois. Define the map π:Gal(KF'/F') → Gal(K/F) by
π(σ) = σ|_K . Show that π is a well-defined injective group
homomorphism.
(8) (15 points) Let ζ = exp(2πi/17) be the primitive 17-th rooth of unity.
2 8 9 15
Show that ζ + ζ + ζ + ζ lies in a degree 4 field extension over Q.
Remark: There are 120 points totally.
注:Q代表有理数体;ε代表属于符号;Z代表整数环;F_3代表order为3的体;σ|_K代表σ限制于K上

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