如果我initial view controller 为Ａ
Ａ会push出B or Ｃ
Ｂ也会push出Ｄ
Ｃ也会push出Ｅ
当我接收到RemoteNotification时
不论当下任何的view controller
我都要push出一个特定的页面
目前我的做法是
在AppDelegate中
- (void)application:(UIApplication *)application
didReceiveRemoteNotification:(NSDictionary *)userInfo {
[PFPush handlePush:userInfo];
NSLog(@"%@",userInfo);
[[NSNotificationCenter defaultCenter] postNotificationName:@"test"
object:nil userInfo:nil];
}
然后每个viewcontroller加上
- (void)viewDidLoad {
[super viewDidLoad];
// Do any additional setup after loading the view, typically from a nib.
[[NSNotificationCenter defaultCenter] addObserver:self
selector:@selector(handleCurrentViewController:) name:@"test" object:nil];
}
- (void)handleCurrentViewController:(NSNotification *)notification {
PushNotificationViewController* pvc = [self.storyboard
instantiateViewControllerWithIdentifier:@"PushNotification"];
[self presentViewController:pvc animated:YES completion:nil];
}
但是如果我现在在Ｂ页面
因为Ｂ是由Ａpush出来的
所以我Ａ跟Ｂ都会接收到NSNotificationCenter的讯息
都会触发
请问如何修改会比较好

在viewWillAppear的时候注册notification,viewWillDisappear的时候移除notificaiton。

我是用一个独立的view去显示，忽略controller