Re: [理工] 一阶正合ODE

楼主: Honor1984 (希望愿望成真)   2017-11-20 16:58:24
※ 引述《wadeinthe (周伟德)》之铭言:
: 积分做起来卡卡的,不知有没有高手肯出手相救
: https://i.imgur.com/LNJrnQP.jpg
: 计算过程有误吗?
(d/dx)sec(x + y^2) + [d/d(x + y^2)]sec(x + y^2) * [(d/dx)(x + y^2) - 1]
+ sqrt(y)dy/dx = 0
=> (d/dx)sec(x + y^2) + (d/x)(2/3)y^(3/2) = 0
=> sec(x + y^2) + (2/3)y^(3/2) = c
作者: wadeinthe (周伟德)   2017-11-20 17:11:00
答案跟我一样,请问计算有错吗?尤其是sec tan 那个积分

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