An automotive event data recorder (EDR) can record a 4-hour high-definition(HD)
video with a fully-charged 1700mAh Li-polymer battery @ 3.7V. A design team is
requested to double the battery use time (i.e. for 8-hour HD video recording)
by reducing the power dissipation of the SOC, which encodes HD video @ 1.3W.
What is the target power dissipation of the new SOC?(Hint: Please calculate
the power dissipation of the whole EDR first.)
张凡的解答
The power dissipation of the whole EDR = 1.7 * 4 * 3.7 = 25.16(这我看得懂)
The current for SOC = (1.3/1.7) = 764.71mAh
The target power dissipation of the new SOC = 764.71mAh * 8 * 3.7 = 22.64W
解答第二行我觉得怪怪的，为什么电流是这样算，而且要降低power dissipation 不是应
该是要降低电压吗?
有没有大大可以帮解