Re: [积分] 星形线参数式

楼主: Honor1984 (希望愿望成真)   2019-02-13 16:50:14
※ 引述《barry881028 (Joker)》之铭言:
: 请问此题的第二小题的星形线参数式是如何得到的呢??
: https://i.imgur.com/vxURpKl.jpg
: https://i.imgur.com/EeSsvxG.jpg
u = x^(1/3)
v = y^(1/3)
u^2 + v^2 = a^(2/3)
=> u = a^(1/3) cosk
v = a^(1/3) sink
=> x = a (cosk)^3
y = a (sink)^3

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