Re: [微方] 参数变异法问题

楼主: Honor1984 (希望愿望成真)   2018-11-15 22:07:26
※ 引述《tratt692 (jech)》之铭言:
: https://i.imgur.com/Awy8CSq.jpg
: 想问这题该怎么解
xy" - (x + 1)y' + y = 0
=> x[y' - y]' - [y' - y] = 0
=> y' - y = Cx
=> y = Aexp(x) - C(x + 1)

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