[微分] 罗毕达

楼主: simcity2013 (ONLY THE STRONG SURVIVE)   2013-11-18 23:08:54
1/n
lim n(2 - 1)
n->∞
1/n
(2 - 1)
= lim
作者: a88241050 (再回頭已是百殘身)   2012-01-18 23:14:00
2^(1/n)对n微分=2^(1/n)*ln2*[?]
作者: newversion (海纳百川)   2013-02-03 04:44:00
严格来说n不连续,不能直接微分 要先换成 2^(1/x)lim n->∞ ... = lim x->∞ ...

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