Re: [极限] 求极限是否存在

楼主: a016258 (憨)   2013-10-29 14:28:39
※ 引述《kylestyle (最近有点烦)》之铭言:
: lim. (csc x)^(sinx)^2
: x→0
: 求板上大大解答 感谢
(省略 x->0)
= lim exp ( -(sinx)^2 * ln(sinx) )
=> lim ( -ln(sinx) / (cscx)^2 )
= lim ( -(cosx/sinx) / -2cscx^2 * cotx )
= lim ( (1/2) ( cosx / sinx ) * [(sinx)^3 / cosx]
= lim ( (1/2) * (sinx)^2 ) = 0
=> exp(0) = 1
有错还请不吝指正...XD
作者: BaBi (迅雷不及掩耳盗铃)   0000-00-00 00:00:00
第四行那边怪怪的, 最后应该是(sin)^2/2~

Links booklink

Contact Us: admin [ a t ] ucptt.com