[问题] 要进入一个使用JSF写的xhtml档,跳出404

楼主: lueichun (no anonymous)   2021-01-01 22:48:04
※状况概述:
我在某个专案内新增一个index.xhtml档,然后输入url想要进入该档案的页面:
http://localhost:8080/TestJPAProject2/index.jsf
※程式码:
web.xml长这样:
<display-name>TestJPAProject2</display-name>
<context-param>
<param-name>com.sun.faces.enableRestoreView11Compatibility</param-name>
<param-value>true</param-value>
</context-param>
<servlet>
<servlet-name>Faces Servlet</servlet-name>
<servlet-class>javax.faces.webapp.FacesServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>Faces Servlet</servlet-name>
<url-pattern>*.jsf</url-pattern>
</servlet-mapping>
作者: fgh81113 (阿景)   2021-01-02 13:13:00
url-pattern 只和 request 有关 response 要看你java里面写了怎么response

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