作者:
wayn2008 (æ¾é¼ )
2020-07-14 22:38:00a^2+ab+b^2 = (a+b)^2-ab = (5-r)^2 + 1/r= 1/r*(r^2-10r+25r+1) = 1/r*(-5r^2+20r) 其他同理整理成 = 1/(abr)*(-5r^2+20r)(-5b^2+20b)(-5a+20a)= -125 abr/(abr)*(r-4)(b-4)(a-4)x^3-5x^2+5x+1=(x-a)(x-b)(x-r) x=4代入等于5答案 = -125*(-5) = 625