Re: [闲聊] 每日leetcode

楼主: SecondRun (雨夜琴声)   2024-06-13 09:05:45
2037. Minimum Number of Moves to Seat Everyone
有 n 个座位和 n 个学生在一个房间里。给你一个长度为 n 的 seats 阵列,其中 seats[i] 是第 i 个座位的位置。同样地,给你一个长度为 n 的 students 阵列,其中 students[j] 是第 j 个学生的位置。
你可以进行以下任意次数的移动:
增加或减少第 i 个学生的位置 1 (即,将第 i 个学生从位置 x 移动到 x + 1 或 x - 1)
返回将每个学生移动到一个座位的最小移动次数,使得没有两个学生在同一个座位上。
请注意,一开始可能有多个座位或学生位于相同位置。
Example 1:
Input: seats = [3,1,5], students = [2,7,4]
Output: 4
Explanation: The students are moved as follows:
- The first student is moved from from position 2 to position 1 using 1 move.
- The second student is moved from from position 7 to position 5 using 2 moves.
- The third student is moved from from position 4 to position 3 using 1 move.
In total, 1 + 2 + 1 = 4 moves were used.
思考: 贪婪
C# code:
public class Solution {
public int MinMovesToSeat(int[] seats, int[] students) {
Array.Sort(seats);
Array.Sort(students);
int result = 0;
int len = seats.Length;
for (int i=0; i<len; i++)
{
result += Math.Abs(seats[i] - students[i]);
}
return result;
}
}
作者: DJYOSHITAKA (Evans)   2024-06-13 09:42:00
别卷了

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