Re: [理工] 拉氏转换解ODE

楼主: Honor1984 (希望愿望成真)   2018-07-30 13:58:32
※ 引述《shirley10631 (leilei_0822)》之铭言:
: https://i.imgur.com/uNZW4DQ.jpg
: 想请教大家这题,我卡在转换那边,有算出答案但跟解答不太一样,麻烦大家帮忙了!
a = 2π
Y = exp(-sa) * [s^2 + 1]^(-1) * (s - 1)/[(s - 1)^2 + 1]
= exp(-sa) * (1/5){-s/(s^2 + 1) - 3/(s^2 + 1) + (s + 1)/[(s - 1)^2 + 1]}
=> y(t) = (1/5){-cos(t-a) - 3sin(t-a) + exp(t-a)[cos(t-a) + 2sin(t-a)]}*u(t-a)
= (1/5){-cos(t) - 3sin(t) + exp(t-a)[cos(t) + 2sin(t)]}*u(t-a)
解答正确
作者: shirley10631 (leilei_0822)   2018-07-30 14:32:00
谢谢H大

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