这题跟前一题条件有关 assume that transactions mayrequires 5 I/O operations另外 最后一行 arrive at the beginning of a 1-sec我觉得这个地方应该是 100us9 transcation * 5 * 20 ms + 100us + 10th transcat阿 我知道了 抱歉 是100ms 没错 我另外打一篇仔细想想是应该还是100us QQtions = 9*5*20ms + 100us + 1*5*20ms = 1.0001sB: 9*5*18ms+ 100us = 810.1ms < 1s∴加上下轮10 transaction 1th and 2th=990.1ms <1s更正 10th 11th transaction