刚刚看到一题,有点疑惑,想问大家 Consider the following hardware configuration. Virtual address=32 bits. Page Size = 4KBytes, and a page table entry occupies 4 bytes. Hoe mamy pages should OS allocate for the pages table of 12 Mbyte process under the following mechanisms. (a) one-level paging 答案是写3 pages, 可是我怎么觉得是3K pages. Process占用了12MB/4KB=3K pages 感觉有点被他的page跟entry混淆了~~