Re: [问卦] 请问这建构式数学的算式应该怎么写?

楼主: giorno78 (天晴)   2023-12-05 19:11:02
Prompt
你是台湾数学系教授。请用台湾建构式数学的算式,写出下面的数学题。文具店卖了2只
蓝笔,后来又卖了3只红笔,请问总共卖了几只蓝笔?
ChatGPT
5
Bing
这是一个简单的问题。文具店卖了2只蓝笔,后来又卖了3只红笔,总共卖了5只笔。
因此,文具店总共卖了 2只蓝笔。
Bard
根据台湾建构式数学的概念,一个数学题可以分为以下几个部分:
背景资讯:描述数学题的情况,例如文具店卖了2只蓝笔和3只红笔。
问题:要找出的问题,例如总共卖了几只蓝笔。
解答:用算式或文字来说明如何解答问题。
因此,用台湾建构式数学的算式来写出这个数学题,可以如下:
背景资讯:
文具店卖了2只蓝笔。
文具店卖了3只红笔。
问题:
总共卖了几只蓝笔?
解答:
蓝笔数量 = 2只蓝笔 + 3只红笔
蓝笔数量 = 5只
因此,答案是 5。
Llama 2
Sure! Here's the solution using Taiwanese constructive mathematics:
Let's denote the number of blue pens sold as "A" and the number of red pens
sold as "B". We know that A + B = 2 (total number of pens sold) and B = 3
(number of red pens sold).
Now, we can construct a equation using these two variables:
A + B = 2
B = 3
We can simplify the equation by substituting B = 3 into the first equation:
A + 3 = 2
Now, we can solve for A by subtracting 3 from both sides:
A = 2 - 3
A = -1
But we know that A cannot be negative, since we are counting the number of
pens sold. So, we can conclude that:
A = 0
Therefore, the number of blue pens sold is 0, and the number of red pens sold
is 3.
※ 引述《gamesame7711 (框框爱安安)》之铭言:
: 文具店卖了2只蓝笔,后来又卖了3只红笔,请问总共卖了几只蓝笔?
: 答案是2只
: 但这题的算式应该怎么写?
: 是 2 + 0 = 2 ? 还是 就2 ?
: 倘 2 + 0 = 2
: 为何又不是 2 + 0 + 0 + 0...= 2?
: 抱歉 数学只有均标
: 这算式应该怎么写才正确?

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