[请益] 循环跳不出来??

楼主: YmemY (**米)   2012-12-18 02:55:26
请教大家,我在做一个一维扩散的模拟,
在我一步一步debug之后,知道问题在循环的部分,好像会无法结束??
可以成功编译成执行档,但一旦开始执行,就无法结束了,也无法输出结果..
以下是程式码,麻烦版有帮我看看哪边出错了??
program diffusion   !1-D diffusion
implicit none
!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
!宣告区
real L,D,J,C,T,F,smallt
!L=length,D=diffusivity,J=diffusion flux,C=initial concentration
!F=Fourier's number, smallt=time interval
real, parameter :: defaultL = 10
real, parameter :: defaultD = 1.03
real, parameter :: defaultJ = 1E-5
real, parameter :: defaultC = 1E-4
real array1(-1:10001),array2(-1:10001)
!the length is divided into 10000 pieces, 10001 nodes, 2 virtual nodes
integer*8 p, pmax, x
!p=pace, x=location
character mode
!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
!输入设定参数
write(*,*) "press ""1"" to select the default values, or""2"" to input
them"
read(*,*) mode
if(mode=="1") then
L = defaultL
D = defaultD
J = defaultJ
C = defaultC
else
write(*,*) "please input the length:"
read(*,*)L
write(*,*) "please input the diffusivity:"
read(*,*)D
write(*,*) "please input the diffusion flux:"
read(*,*)J
write(*,*) "please input the initial concentration:"
read(*,*)C
end if
write(*,*) "please input the time:"
read(*,*)T
!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
!计算用到的参数
smallt = 0.25*L*L/D/10**8
pmax = T/smallt
F = D*smallt/(L*L)*10**8
array1 = C
array2 = C
!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
!这里就是出错的开始!!!
do p=1,pmax
do x=0,10000
array1(-1) = J*L/10000/D + array1(0)
array1(10001) = array1(10000) + array1(0) - array1(-1)
array2(x)=F*(array1(x+1)+array1(x-1))+(1-2*F)*array1(x)
end do
array1 = array2
end do
!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
!将阵列输出到文字档
open(unit=10,file="diffusion1.txt")
do x=-1,10001
write(10,*) array1(x)
end do
STOP
END
作者: Cypresslin (啊哈哈~~)   2012-02-18 09:52:00
应该不是无法结束,是循环太大,pmax还要乘上10000
作者: kkarthur (aa)   2012-02-18 12:25:00
smallt = 0.25*L*L/D/10**8 检查你的smallt的值如果没有意外应该是0,导致pmax极大,循环跑不完改成smallt = 0.25*L*L/D/10.0**8.0 试试看不仅是这个地方,例如array1(-1) = J*L/10000/D这都会'让你的结果与预期的不同
作者: mk650   2012-02-18 13:56:00
t=10,pamx=41200000,x=412000000000,粉大的循环,如果参数没错,也只能丢著给它跑啦
作者: Cypresslin (啊哈哈~~)   2012-02-18 13:57:00
你可以再把循环里跟x无关的拿出来,可能可以快一咪咪
作者: mk650   2012-02-18 14:00:00
呵三楼的精简化本人常干,不过它这个程式很简单,只有两行多余差别不大啦.重点在t要多大,t=0.0001够吗?t=1,十分钟跑完,I7 2600套装很便宜电脑,更好的电脑得会更快这样很快了,我的程式都要跑一周以上,有三周还没跑完的
作者: george1224 ( )   2012-02-19 22:32:00
建议把你所计算的数值的order提高一点,电脑在进行计算的时候,其精度会有差别...

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