;with tb1 as (
select User,SEQ,Time,
num = row_number() over (partition by User,SEQ order by Time)
from test
)
select t1.User,t1.SEQ,
开始 = t1.Time,
结束 = isnull(t2.Time,getdate())
from tb1 t1 left join tb1 t2
on t1.User = t2.User and t1.SEQ + 1 = t2.SEQ and t1.num = t2.num
where t1.num = 1
※ 引述《carsun00 (永夜)》之铭言：
: 数据库名称：SQL Server 2017
: 数据库版本：14.0.2002.14
: 内容/问题描述：
: 资料来源是状态&Time的资料表
: 需要转换成开始与结束的资料格式
: 同时可能会有多笔开始多笔结束
: 要取出最早时间与最晚时间
: 是有想出一个堪用的语法...
: 但是想知道有没有比较好的做法..
: 资料如下
: User SEQ Time
: AA 1 2019-05-10 09:00:00.000
: AA 1 2019-05-10 20:00:00.000
: AA 2 2019-05-11 10:00:00.000
: AA 2 2019-05-11 20:00:00.000
: 人| Seq|开始 | 结束
: AA| 1 |2019-05-10 09:00:00.000 | 2019-05-11 10:00:00.000
: AA| 2 |2019-05-11 10:00:00.000 | 现在时间
: seq2的起始时间要当作 seq1的结束时间。
: 没有下一笔资料，抓现在GetDate()
: SQL语法如下
: SELECT
: StartData.[User]
: , StartData.[Start_Date_Time]
: , EndData.[End_Date_Time]
: FROM
: ( SELECT
: ROW_NUMBER() OVER(PARTITION BY [User] ORDER BY
: CONVERT(VARCHAR(20), [Time], 111)) AS Num
: , 1 + ROW_NUMBER() OVER(PARTITION BY [User] ORDER BY
: CONVERT(VARCHAR(20), [Time], 111)) AS Num2
: , [User]
: , CONVERT(VARCHAR(20), [Time], 111) AS [Start_Date_Time]
: FROM
: [TEST]
: GROUP BY
: [User]
: , CONVERT(VARCHAR(20), [Time], 111)
: ) AS StartData
: LEFT JOIN
: ( SELECT
: ROW_NUMBER() OVER(PARTITION BY [User] ORDER BY
: CONVERT(VARCHAR(20), [Time], 111)) AS Num3
: , [User], CONVERT(VARCHAR(20), [Time], 111) AS [End_Date_Time]
: FROM
: [TEST]
: GROUP BY
: [User]
: , CONVERT(VARCHAR(20), [Time], 111)
: ) AS EndData
: ON StartData.[User] = EndData.[User]
: AND StartData.Num2 = EndData.Num3