开发平台(Platform): (Ex: Win10, Linux, ...)
macOS high Sierra
编译器(Ex: GCC, clang, VC++...)+目标环境(跟开发平台不同的话需列出)
XCode
额外使用到的函数库(Library Used): (Ex: OpenGL, ...)
no
问题(Question)：
我设一个父类别,并且能让子类别可以overrride
然后在main function初始化父类别，并且借由一些条件（终端机上的指令）来触发子类别
但是最后出现bug,
Undefined symbols for architecture x86_64:
ld: symbol(s) not found for architecture x86_64
clang: error: linker command failed with exit code 1 (use -v to see invocation)
[Finished in 0.6s with exit code 1]
想请教一下版上高手们，如何解决这问题
谢谢
喂入的资料(Input)：
没
预期的正确结果(Expected Output)：
子类别在条件触发后，能成功初始化
错误结果(Wrong Output)：
compile的时候出现错误讯息如下
Undefined symbols for architecture x86_64:
"ShortJobFirst::ShortJobFirst()", referenced from:
SchInitial(std::__1::basic_string<char, std::__1::char_traits<char>, std::__1::allocator<char> >&, int&, std::__1::basic_string<char, std::__1::char_traits<char>, std::__1::allocator<char> >&) in lab2-d65f71.o
"RR::RR(int)", referenced from:
SchInitial(std::__1::basic_string<char, std::__1::char_traits<char>, std::__1::allocator<char> >&, int&, std::__1::basic_string<char, std::__1::char_traits<char>, std::__1::allocator<char> >&) in lab2-d65f71.o
"FCFS::FCFS()", referenced from:
SchInitial(std::__1::basic_string<char, std::__1::char_traits<char>, std::__1::allocator<char> >&, int&, std::__1::basic_string<char, std::__1::char_traits<char>, std::__1::allocator<char> >&) in lab2-d65f71.o
"LCFS::LCFS()", referenced from:
SchInitial(std::__1::basic_string<char, std::__1::char_traits<char>, std::__1::allocator<char> >&, int&, std::__1::basic_string<char, std::__1::char_traits<char>, std::__1::allocator<char> >&) in lab2-d65f71.o
"PRIO::PRIO(int)", referenced from:
SchInitial(std::__1::basic_string<char, std::__1::char_traits<char>, std::__1::allocator<char> >&, int&, std::__1::basic_string<char, std::__1::char_traits<char>, std::__1::allocator<char> >&) in lab2-d65f71.o
ld: symbol(s) not found for architecture x86_64
clang: error: linker command failed with exit code 1 (use -v to see invocation)
程式码(Code)：(请善用置底文网页, 记得排版，禁止使用图档)
https://ideone.com/ZskhiK
因为是一个练习scheduling的习题
所以不po全部的程式码
仅就问题讨论
补充说明(Supplement)：
无