https://i.imgur.com/uv6vpSh.png
米妈刻在基改番茄内的讯息
"I will always be attached to you, Miorine" 我将永远与你在一起 米奥林涅
这段讯息一看就不是套DNA codon的写法
因为DNA转胺基酸后,要用胺基酸简称套26字母还差 b,j,o,u,x,z
实际上把那段DNA序列丢去转只会得到这个鬼东西
GTC-CGG-CCG-AGA-AGT-AGT-CGG-AAA-AGT-CCG-AAA-CGA-CAG-CGG-AAC-ACA-CGG-AAA-CAT-
CAT-AAA-AAG-ACT-ACA-AAT-CGG-CAT-ATG-CGG-CGA-ATG-CCA
-> VRPRSSRKSPKRQRNTRKHHKKTTNRHMRRMP
所以他应该是把ATCG重新编码,因为字母下面有白色方块跟黑色方块
A=[0,0] T=[1,1] C=[0,1] G=[1,0]
因此 CCG=[0,1][0,1][1,0]
再把 CCG=w 跟其他有出现的小写字母套进去就可以得出下面的密码表
大写只出现两个 (GTC=I=101101, TAC=M=110001)就不知道规律
a = [0,0,0,0,0,0]
b = [0,0,0,0,0,1]
c = [0,0,0,0,1,0]
d = [0,0,0,0,1,1]
e = [0,0,0,1,0,0]
f = [0,0,0,1,0,1]
g = [0,0,0,1,1,0]
h = [0,0,0,1,1,1]
i = [0,0,1,0,0,0]
j = [0,0,1,0,0,1]
k = [0,0,1,0,1,0]
l = [0,0,1,0,1,1]
m = [0,0,1,1,0,0]
n = [0,0,1,1,0,1]
o = [0,0,1,1,1,0]
p = [0,0,1,1,1,1]
q = [0,1,0,0,0,0]
r = [0,1,0,0,0,1]
s = [0,1,0,0,1,0]
t = [0,1,0,0,1,1]
u = [0,1,0,1,0,0]
v = [0,1,0,1,0,1]
w = [0,1,0,1,1,0]
x = [0,1,0,1,1,1]
y = [0,1,1,0,0,0]
z = [0,1,1,0,0,1]
BTW 别叫chatGPT把你要的字母转成DNA序列,会跟叫他算数学一样出错
就算用gpt4.0 忽略DNA规则也一样
米妈这讯息应该是包在基改番茄的注册DNA序列里面,用来标记这颗是NR400。
所以他们查primer set就发现这段讯息
不然去扫全部genome non-coding region找隐藏讯息....真浪漫啊 呵呵