Re: [请益] 一个 OS 的笨问题... =.=

楼主: upanddn (小管)   2005-03-11 02:37:44
※ 引述《jerryr (灰色的苦涩 .....)》之铭言:
: Each page-table entry is usually 4 bytes long,
: but that size can vary as well. A 32-bit entry
: can point to one of 2(32) physical page frames.
: If a frame is 4 KB, then a system with 4-byte
: entries can address 2(36) bytes (or 64 GB) of
: physical memory.
: Note: 2(32) 表示 2 的 32 次方 ....
: 请问一下...
: 关于下面那个 2 的 36 次方 我怎样也算不出来.... :(
: 有人可以告诉我 怎么算的吗 ....
: 谢谢
2^36=2^6*2^30(2^30=1GB)
=2^6GB
=64GB
有错请指教。

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