程式码如下：
var random = new Array();
random[0] = Math.floor(Math.random()*10);
random[1] = Math.floor(Math.random()*10);
random[2] = Math.floor(Math.random()*10);
random[3] = Math.floor(Math.random()*10);
random[4] = Math.floor(Math.random()*10);
random[5] = Math.floor(Math.random()*10);
random[6] = Math.floor(Math.random()*10);
random[7] = Math.floor(Math.random()*10);
random[8] = Math.floor(Math.random()*10);
random[9] = Math.floor(Math.random()*10);
for(var i = 0 ; i < 10 ; i++){
if(random[i] == random[i+1]){
random[i+1] = Math.floor(Math.random()*10);
i

http://jsbin.com/liyaso先把要出现的数字选出来在洗牌阿

把值塞进array里再shuffle...大概像这样 http://goo.gl/6xayg

谢谢两位大大，已解决，洗牌这事情比我原先想的好太多