Re: [积分] 基本的三角积分
楼主: Honor1984 (希望愿望成真) 2014-04-09 16:57:09
※ 引述《kstmasa (鸡排)》之铭言：
:
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: 如图
: (抱歉，用打的我不太会)
∫[sin(x)]^2 dx
= ∫ [1 - cos(2x)]/2 dx
= x/2 - sin(2x)/4
∫ [sin(x/6)]^3 dx
= ∫[-1 + cos(x/6)]/2 * 6 dcos(x/6)
= -3cos(x/6) + 3/2 * [cos(x/6)]^2
:
: 如图
: (抱歉，用打的我不太会)
∫[sin(x)]^2 dx
= ∫ [1 - cos(2x)]/2 dx
= x/2 - sin(2x)/4
∫ [sin(x/6)]^3 dx
= ∫[-1 + cos(x/6)]/2 * 6 dcos(x/6)
= -3cos(x/6) + 3/2 * [cos(x/6)]^2